recursively count the words occurrence in the text files
Phil Meyer
pmeyer at themeyerfarm.com
Thu Dec 30 18:48:36 UTC 2010
On 12/30/2010 11:34 AM, S Mathias wrote:
> mkdir one
> mkdir two
> mkdir three
>
> echo "word1 word2 word3"> one/asf.txt
> echo "word2 word4, word5"> one/asfcxv saf.txt
> echo "word1. word2"> one/dsgsdg.txt
>
> echo "word6, word3!"> two/sdgsd dsf.txt
> echo "word6"> two/ergd.txt
>
> echo "asdf, word2"> three/werdf.txt
> echo "word7, word8 word9 word10"> three/qwerb erfsdgdsg.txt
> echo "word4 word3"> three/web erg as.txt
>
Simplest would be:
grep -r -c word one two three
which produces:
one/asfcxv:1
one/asf.txt:1
one/dsgsdg.txt:1
two/ergd.txt:1
three/web:1
three/werdf.txt:1
three/qwerb:1
There are other options that will give you more precision, but basically
I think that grep will give you what you want.
(If I understodd the question ... )
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