[OT] general C++ question
Christoph Höger
choeger at cs.tu-berlin.de
Thu Sep 2 13:23:54 UTC 2010
Am Donnerstag, den 02.09.2010, 12:54 +0200 schrieb Michael Schwendt:
> On Thu, 02 Sep 2010 12:15:27 +0200, Christoph wrote:
>
> > Hi all,
> >
> > I just learned about closures in the Boost library and wanted to write
> > some shorter code. To test, I used the following snippet:
> >
> > #include <iostream>
> > #include <string>
> >
> > #include <boost/function.hpp>
> > #include <boost/bind.hpp>
> >
> > class FakeVisitor {
> > public:
> > virtual void visit(int e) {}
> > virtual void visit(std::string e) = 0;
> > };
> >
> > template <typename T> class GenericVisitor : public FakeVisitor {
> > public:
> > boost::function<void (T e)> f;
> > virtual void visit(T e) { f(e); }
> > };
> >
> > void print(int a, int i) {
> > std::cout << a << ":" << i << std::endl;
> > }
> >
> > int main(int argc, char** argv) {
> > GenericVisitor<int> v;
> > v.f = boost::bind(&print, 0, _1);
> >
> > v.visit((int) 1);
> > v.visit(std::string("hallo"));
> > //boost::bind(print, 1, _1)(2);
> > }
> >
> > Apparently, it does not work. Does anyone know why GenericVisitor<int>
> > does not inherit visit(std::string)?
>
> It does, but it's still declared a pure virtual function, i.e.
> FakeVisitor (and GenericVisitor, too) is an abstract class that
> cannot be instantiated. You would need to declare an implementation
> of the visit(std::string) virtual method in GenericVisitor to make
> it a non-abstract type.
Ah, sorry, wrong snippet. It does not work with
virtual void visit(std::string e) {}
in FakeVisitor.
The intention is to extend a visitor pattern with a templated class that
overloads exactly one method.
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