variable in loop

[Rodolfo Alcazar Portillo]

On Sun, 2011-01-02 at 14:27 -0800, S Mathias wrote:
> $ ASDF=hello; a=0; a=$(( 70 - $(echo $ASDF | awk '{print length}') )); echo "$a $ASDF"$(for i in {1..$a}; do printf "."; done)
> 65 hello.
> $ 
> Why doesn't it print:
> 65 hello.................................................................

You wrote:  for i in {1..$a}
I think you mean: for ((i=1;i<$a;i++))

Cheers.
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Rodolfo Alcazar Portillo - nospaze at gmail.com
otbits.blogspot.com / counter.li.org: #367962
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