Hi,

I think the problem is in the connect itself.

The standard transport included in suds assumes that only the SOAP calls may need authentication or other things. Downloading the WSDL is attempted with a plain HTTP GET (Not even POST is allowed)

I guess that the transport covers at least 95% of standard situations, but it didn't for example cover mine, where I wanted to embed the WSDSL as a string in my code. Of course only with my own transport I could give suds a "file" object with the content of the string.

It is my feeling that a better transport could be written (we have seen some examples shared in the mailing list) although some use cases may require re-thinking how a Client is initialized.

In the case pertaining to Janet, I guess she may download the WSDL file as you suggest, pass it to the transport hack below. She may then use this transport during client initialization. Obviously this is only good for 1 WSDL file. (The transport below can also load WSDL content directly from a string)

    class TransportHack(Transport):
        def __init__(self, wsdlFile=None, **kwargs):
            Transport.__init__(self, **kwargs)
            self.wsdlcontent = wsdlFile

        def open(self, request):
            if self.wsdlFile is not None:
                return self.wsdlFile

            log.debug('opening: (%s)', request.url)
            fp = None
            location = request.url.lstrip()
            if location.startswith('<?'):
                log.debug('returning url (%s) as StringIO file')
                fp = StringIO(location)
            else:
                parsed = urlparse(request.url)
                if parsed.scheme == 'file':
                    log.debug('opening file (%s) with open', parsed.path)
                    try:
                        fp = open(parsed.path)
                    except Exception, e:
                        raise TransportError(str(e), 503, StringIO(''))
                else:
                    log.debug('opening scheme (%s) over the network', parsed.scheme)
                    try:
                        url = request.url
                        log.debug('opening (%s)', url)
                        u2request = u2.Request(url)
                        self.proxy = self.options.proxy
                        return self.u2open(u2request)
                    except u2.HTTPError, e:
                        raise TransportError(str(e), e.code, e.fp)
            return fp

Then do something like

myClient = suds.client.Client(wsdl, transport=HackTransport(fileFromU2), etc)

Best regards

Daniel

On Wed, Oct 6, 2010 at 21:22, Joshua J. Kugler <joshua@eeinternet.com> wrote:

On Wednesday 06 October 2010, Janet Valbuena elucidated thus:
> Hi
>
> I'm new to suds (have just downloaded it after getting frustrated
> with SOAPpy).
>
> I'm trying to connect to a WSDL which requires basic HTTP
> authentication. I have been able to connect to it correctly using PHP
> but I need to use Python.
>
>
> This is my code:
>
> #!/usr/bin/python
>
> Username = "user"
> Password = "pass123"
> from suds.transport.http import HttpAuthenticated
> t = HttpAuthenticated(username=Username, password=Password)
>
> # WSDL is only available in internal network
> WSDL = "http://localhost:18080/external/services/DomService?wsdl"
> from suds.client import Client
> client = Client(WSDL, transport=t)
>
>
>
>
> And this is the error it returns:
>
> Traceback (most recent call last):
>   File "./wsdltest.py", line 25, in <module>
>     client = Client(wsdl, transport=t)
>   File "build/bdist.linux-i686/egg/suds/client.py", line 112, in
> __init__ File "build/bdist.linux-i686/egg/suds/reader.py", line 152,
> in open File "build/bdist.linux-i686/egg/suds/wsdl.py", line 136, in
> __init__ File "build/bdist.linux-i686/egg/suds/reader.py", line 79,
> in open File "build/bdist.linux-i686/egg/suds/reader.py", line 101,
> in download File "build/bdist.linux-i686/egg/suds/sax/parser.py",
> line 136, in parse File "/usr/lib/python2.5/xml/sax/expatreader.py",
> line 107, in parse xmlreader.IncrementalParser.parse(self, source)
>   File "/usr/lib/python2.5/xml/sax/xmlreader.py", line 125, in parse
>     self.close()
>   File "/usr/lib/python2.5/xml/sax/expatreader.py", line 217, in
> close self.feed("", isFinal = 1)
>   File "/usr/lib/python2.5/xml/sax/expatreader.py", line 211, in feed
>     self._err_handler.fatalError(exc)
>   File "/usr/lib/python2.5/xml/sax/handler.py", line 38, in
> fatalError raise exception
> xml.sax._exceptions.SAXParseException: <unknown>:1:0: no element
> found

I would try to download the file with a quick urllib2 script and see
what you get.  The error is not in the connect (that would raise its
own exception) but in trying to parse what *is* being downloaded.

Something like:

import urllib2
auth_handler = urllib2.HTTPBasicAuthHandler()
auth_handler.add_password(realm='name_of_your_realm',
                          uri='your_url_without_the_file_name',
                          user=User,
                          passwd=Password)
opener = urllib2.build_opener(auth_handler)
urllib2.install_opener(opener)

print urllib2.open(WSDL).read()

j

--
Joshua Kugler
Part-Time System Admin/Programmer
http://www.eeinternet.com - Fairbanks, AK
PGP Key: http://pgp.mit.edu/  ID 0x73B13B6A
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