Re: bash line feeds in a variable problem

[ToddAndMargo]

On 1/20/22 13:42, Cameron Simpson wrote:
> On 19Jan2022 20:32, ToddAndMargo  wrote:
> > into a variable
> > X=$(curl -s ipinfo.io -o -)
>
> That is robust (well, it loses trailing whitespace).
> > But I lose all my line feeds when I
> >     echo -e $X
> > How do I get my line feeds back?
>
> Quotes.
>  echo -e "$X"
>
> Unquoted it is broken into "words" on whitespace, and echo prints the
> words with a single space between each. With quotes, echo has exactly 1
> argument, the string in $X.
>
> Oh, and try to use $lowercase variables for unexported/nonconfiguration
> variables.
>
> But add tz says, if it is JSON, better to parse the JSON if you're
> picking things out of it.
>
> Cheers,
> Cameron Simpson

Thank you!