Re: variable in loop

[Roberto Ragusa]

Rodolfo Alcazar Portillo wrote:
> On Sun, 2011-01-02 at 14:27 -0800, S Mathias wrote:
> > $ ASDF=hello; a=0; a=$(( 70 - $(echo $ASDF | awk '{print length}') )); echo "$a $ASDF"$(for i in {1..$a}; do printf "."; done)
> > 65 hello.
> > $ 
> > Why doesn't it print:
> > 65 hello.................................................................
>
> You wrote:  for i in {1..$a}
> I think you mean: for ((i=1;i<$a;i++))

Right, but with

i=0

or

i<=$a

to have an accurate count ;-)