3 Jan
2011
3 Jan
'11
1:14 a.m.
On Sun, 2011-01-02 at 14:27 -0800, S Mathias wrote:
$ ASDF=hello; a=0; a=$(( 70 - $(echo $ASDF | awk '{print length}') )); echo "$a $ASDF"$(for i in {1..$a}; do printf "."; done) 65 hello. $ Why doesn't it print: 65 hello.................................................................
You wrote: for i in {1..$a} I think you mean: for ((i=1;i<$a;i++))
Cheers. ---------------------------------------------- Rodolfo Alcazar Portillo - nospaze@gmail.com otbits.blogspot.com / counter.li.org: #367962 ---------------------------------------------- "Früher oder später emulieren wir euch." - linux.de