Re: bash line feeds in a variable problem

[Todd Zullinger]

ToddAndMargo via users wrote:
> I am trying to get
> curl -s ipinfo.io -o -
>
> into a variable
> X=$(curl -s ipinfo.io -o -)
>
> But I lose all my line feeds when I
> echo -e $X
>
> How do I get my line feeds back?

Quote the variable.  You don't need -e; echo "$X" works.

But with JSON data being returned, it would seemingly make
more sense to parse the data and extract what you want:

ipinfo=$(curl -s ipinfo.io)
    city=$(jq -r .city <<<$ipinfo)

or just:

city=$(curl -s ipinfo.io | jq -r .city)