xargs +sed question

Matthew Miller mattdm at mattdm.org
Thu Dec 7 02:36:54 UTC 2006


On Thu, Dec 07, 2006 at 02:31:56AM +0000, Amadeus W. M. wrote:
> I'd normally ask this in comp.os.linux.misc, but my news server is not
> responding, so I'm asking it here.
> I have a bunch of files in a directory tree in which I want to replace a
> string A with string B. I'm trying to do this with xargs like so:
> grep -ri -l A . | xargs sed -e 's/A/B/g'
> and this does what I want, except, of course, that it outputs everything
> to stdout. Is there any way to pass the name of each input file as
> output for sed? 

You want the "sed -i" option, which edits files in place. (I believe this is
a GNU extension.)


-- 
Matthew Miller           mattdm at mattdm.org          <http://mattdm.org/>
Boston University Linux      ------>              <http://linux.bu.edu/>




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