OT: simple regex question

[Khoa Ton]

Dario Lesca wrote:
 > Hi, how to found into string 2 or more word, only if are all present?
 >
 > % echo "aa bb cc dd"|egrep -q '(bb|dd)' && echo found
 >
 > This command show "found" if bb OR dd are in string.
 > But if I want show "found" only if bb AND dd are present into string.
 >
 > What egrep (or sed) command I must use?

I know Matt solved this with some impressive perl-fu, but here's a solution
just so grep doesn't feel left out :-)

text="aa bb cc dd"; echo " $text " | egrep -qe '( aa( .+)* dd )|( dd( .+)* aa )' && echo found

Khoa