[Fwd: User account ( hacked ) of FC6 System]

[edwardspl at ita.org.mo]

Les Mikesell wrote:

>edwardspl at ita.org.mo wrote:
>
>  
>
>>>>chmod g+rwx ( What number of g+rwx, eg : ?77 ) /home/edward
>>>>        
>>>>
>>>You can use the symbolic form literally. I think it's easier to
>>>understand. Let the computer do the binary/octal math.
>>>g+rwx means add the read, write, and execute bits for the group.
>>>      
>>>
>>But I want to know what no of g+rwx...
>>    
>>
>
>The + means it is added to the bits already permitted.  Look at them as
>groups of 3 bits in binary and take the octal value.
>
> user   group    other
> rwx    rwx     rwx
>
>You'll start with a home dir having rwx --- ---  so that's 111 000 000
>binary or 700 octal.
>Add  the group rwx and you get 111 111 000 or 770 octal
>  
>
So, g+rwx = 770, right ?

>>>>chmod +t ( What number of +t ) /home/edward
>>>>        
>>>>
>
>That's one more bit to the left, 1 000 000 000  binary, so 1000 octal.
>Add that to what you have.
>
>  
>
>>>Same here, you can type it that way and it means add the "sticky" bit.
>>>      
>>>
>>Also want to know...
>>    
>>
>
>Altogether, the octal value for the mode ends up at 1770.  But, as I
>said before the computer does a better job of thinking in octal.
>  
>
So, +t = 1770, right ?

Edward.
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