that old GNU/Linux argument

[Kevin J. Cummings]

Antonio Olivares wrote:
>> $ cat /etc/redhat-release
>> Fedora release 8 (Werewolf)
>> $ uname -o
>> GNU/Linux
>>
>> John
>>
>> -- 
> 
> Tried this command in slax
> uname -o which according to man uname 
>        -o, --operating-system
>               print the operating system
> 
> Slax is based on Slackware Linux, here's the result(s)
> 
> root at slax:~# cat /etc/slax-version
> Slax 6.0.7
> root at slax:~# cat /etc/slackware-version
> Slackware 12.1.0
> root at slax:~# uname -o
> GNU/Linux
> 
> 
> It is GNU/Linux.  Should this be tried with Ubuntu, Suse, Gentoo, ..., etc?

Let's see:

rpm -qf `which uname`
coreutils-6.10-27.fc9.x86_64

and of course rpmq -i coreutils:
> Name        : coreutils                    Relocations: (not relocatable)
> Version     : 6.10                              Vendor: Fedora Project
> Release     : 27.fc9                        Build Date: Fri 04 Jul 2008 12:37:00 PM EDT
> Install Date: Wed 09 Jul 2008 02:15:25 PM EDT      Build Host: x86-5
> Group       : System Environment/Base       Source RPM: coreutils-6.10-27.fc9.src.rpm
> Size        : 11290040                         License: GPLv3+
> Signature   : DSA/SHA1, Tue 08 Jul 2008 11:23:50 AM EDT, Key ID b44269d04f2a6fd2
> Packager    : Fedora Project
> URL         : http://www.gnu.org/software/coreutils/
> Summary     : The GNU core utilities: a set of tools commonly used in shell scripts
> Description :
> These are the GNU core utilities.  This package is the combination of
> the old GNU fileutils, sh-utils, and textutils packages.

So, you want to use a GNU utility to "prove" that the OS is GNU/Linux? 
Sounds rather like GNU made an assertion and is using that assertion as 
a proof.

BTW, I wouldn't have expected a package of GNU utilities to say anything 
else.

-- 
Kevin J. Cummings
kjchome at rcn.com
cummings at kjchome.homeip.net
cummings at kjc386.framingham.ma.us
Registered Linux User #1232 (http://counter.li.org)