variable in loop
Roberto Ragusa
mail at robertoragusa.it
Mon Jan 3 08:41:19 UTC 2011
Rodolfo Alcazar Portillo wrote:
> On Sun, 2011-01-02 at 14:27 -0800, S Mathias wrote:
>> $ ASDF=hello; a=0; a=$(( 70 - $(echo $ASDF | awk '{print length}') )); echo "$a $ASDF"$(for i in {1..$a}; do printf "."; done)
>> 65 hello.
>> $
>> Why doesn't it print:
>> 65 hello.................................................................
>
> You wrote: for i in {1..$a}
> I think you mean: for ((i=1;i<$a;i++))
Right, but with
i=0
or
i<=$a
to have an accurate count ;-)
--
Roberto Ragusa mail at robertoragusa.it
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