Bash: (foo==0)?foo=1:foo=0 valid?

[Marko Vojinovic]

On Saturday 02 July 2011 18:50:46 Joe Zeff wrote:
> On 07/02/2011 10:45 AM, Daniel B. Thurman wrote:
> > I seem to forget my shell programming
> > but is the following statement valid?
> > 
> > ($foo==0)?foo=1:foo=0
> > 
> > I thought it was called the tristate conditional
> > operator but in any case I could not find it in
> > google.
> 
> I don't know if it's allowed in bash, or any other shell.  I do know,
> however, that it's a valid construct in C.

With a small detail that the "$" in "$foo" is not actually a valid C construct 
itself, right?

Or were you looking at the subject line, where the code doesn't have the "$"? 
;-)

Best, :-)
Marko