BASH and wildcard expansion

[Bill Oliver]

On Mon, 19 Aug 2013, Mark Haney wrote:

> I've hit a problem I can't quite figure out which a bash script I'm writing.  I'm trying to copy backup files in the format 2013-August-18--1123.zip to an NFS share.
>  I want to have the script copy the file with just the date.  In bash I've setup vars that get the current date:
> # Date variables
> log_year=`date "+%Y"`
> log_month=`date "+%B"`
> log_day=`date "+%d"`
> 
> # Filename format YYYY_MM_DD--HHMM.zip
> filename=$log_year"-"$log_month"-"$log_day"--"/*".zip"
> 
> The problem is I don't really care about the stuff after the '--'. I.e. from the CLI I'd just 'ls 2013-August-18--*.zip' to get all the files with that date in the
> file name.  How can I do that in a bash script?
> 
> 
> --
> Caesar si viveret, ad remum dareris.
> 
> Mark Haney
> Software Developer/Consultant
> mark.haney at gmail.com
> 
>


You mean something like this?

************************
#!/bin/sh
# Date variables
log_year=`date "+%Y"`
log_month=`date "+%B"`
log_day=`date "+%d"`

# Filename format YYYY_MM_DD--HHMM.zip
filename="$log_year-$log_month-$log_day--*.zip"

filelist=`ls $filename`

echo $filelist
***************************

billo