Manipulating journalctl output

[Suvayu Ali]

On Wed, Jan 01, 2014 at 11:52:04PM +0100, Mateusz Marzantowicz wrote:
> On 01.01.2014 20:57, Suvayu Ali wrote:
> 
> > Now my questions:
> > 
> > 1. How can I filter messages printed to the logs from my cron jobs?  I
> >    will try to explain by example:
> > 
> >      $ journalctl -ru crond --since=-3d
> >      -- Logs begin at Sun 2013-11-17 02:48:46 CET, end at Wed 2014-01-01 20:31:27 CET. --
> 
> # journalctl -u crond.service
> 
> Do it as root, and add .service suffix to crond.
> 
> Bash completion is your friend here, hitting TAB twice after -u option
> will give you units that are recognized.
> 
> journalctl is user-aware and show only what's appropriate.

Actually, if I'm in the systemd-journal group it is equivalent.  That
said, I get the same output as root.  I use bash-completion, and the
.service is optional when used with -u (as I mentioned in my email).  I
tried with and without the .service.  It works both ways for sendmail,
just not crond.

Cheers,

-- 
Suvayu

Open source is the future. It sets us free.