Thanks for a rapid reply.
No, no leading tab. The value in the database is and was always ok and
without 'tab'. (your strings command gives me '=user1'). I was simply
creating a perl script and saw that if i enter the uid with or without
tab the ldap server returns the entry anyway which i found to be
strange because i escape the values in the filter...
You can add '\09' in the beginning and/or at the end of any ldap
filter and it continues to work with FDS (you can try on your own
server smth like "(uid=\09rmeggins\09\09)"...
Don't know whether it is normal :)
2008/4/7, Rich Megginson <rmeggins(a)redhat.com>:
Andrey Ivanov wrote:
> Hi,
>
> I don't know whether it is a bug or a feature. If i make an ldapsearch
> (or a search by perl LDAP) the ESCAPED tab is not taken into account :
> the search
> ldapsearch -x -D... -h <server> -b "<base>"
"(uid=\09user1\09)"
>
> gives the same result (the entry corresponding to user1) as
> ldapsearch -x -D... -h <server> -b "<base>"
"(uid=user1)"
>
> The logs show that the filter makes successfully its way to the ldap core:
> 07/Apr/2008:16:03:30 +0200] conn=85418 op=3 SRCH base="..." scope=2
> filter="(uid=\09user1\09)" attrs=ALL
>
> 07/Apr/2008:16:03:45 +0200] conn=85418 op=3 SRCH base="..." scope=2
> filter="(uid=user1)" attrs=ALL
>
> How do i search then the attribute that starts with the tab symbol (\09)?
>
>
If you do a "strings
/var/lib/dirsrv/slapd-instance/db/userRoot/uid.db4" do you
see the value with the leading tab character?
>
> Thank you!
>
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