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13 years, 6 months
Re: [Fedora-suds-list] Error connecting to WSDL that requires authentication
by Janet Valbuena
Hi Daniel
This still doesn¹t make sense.
I understand you¹re suggesting this:
WSDL = "http://localhost:18080/external/services/DomService?wsdl"
User = ³user1²
Password = ³pass123²
# Is this OK?
URI = "http://localhost:18080/²
# What should the realm be? Is this OK?
Realm = ³external/services/DomService²
import urllib2
auth_handler = urllib2.HTTPBasicAuthHandler()
auth_handler.add_password(realm=Real, uri='your_url_without_the_file_name',
user=User, passwd=Password)
>>>> opener = urllib2.build_opener(auth_handler)
>>>> urllib2.install_opener(opener)
>>>>
fileFromU2 = urllib2.open(WSDL)
#Note that up to this point, the code doesn¹t show any errors but
fileFromU2.read () is an empty string.
# Then I¹m supposed to use the transport hack class:
myClient = suds.client.Client(WSDL, transport=HackTransport(fileFromU2),
etc)
# The question is, why should I pass fileFromU2 as a transport parameter,
when what I¹m trying to get through calling the Client is precisely that
WSDL?
What I¹m really hoping to do (in case I haven¹t been clear) is something
like this:
# Assuming the authorisation issue is solved somehow by producing a t¹
parameter to pass on here:
myClient = suds.client.Client(WSDL, transport=t)
# Call some of the methods available in the WSDL, for example:
Result = myClient.createAccount({³name²:²janet², ³phone²: ³8989898989²,
³address²:²12 Victoria St², ³city²:²Manly², ³email²: ³janet(a)blahh.com2})
Is perhaps suds.client.Client NOT the class I need?
Thanks again for your time and answers in advance.
Cheers
Janet
On 7/10/10 21:42, "Daniel Rodriguez" <danjrod(a)gmail.com> wrote:
> Hi Janet,
>
> The code provided by Joshua lets you download the WSDL to a "file" object.
> That's why the last statement of his example is:
>
>> print urllib2.open(WSDL).read()
>
> whis is basically first opening a file (open), then reading the content to a
> string (read) and printing it to standard output. If you simply do:
>
>> fileFromU2 = urllib2.open(WSDL)
>
> you get direct acess to the file object and can pass it to the hacked
> transport I provided before.
>
> Best regards
>
> Daniel
>
> On Thu, Oct 7, 2010 at 13:03, Janet Valbuena <janet.valbuena(a)tpp.com.au>
> wrote:
>> Joshua, Daniel
>>
>> Thanks very much for your quick response.
>>
>> I tried Joshua¹s suggestion but it didn¹t work.
>>
>> I don¹t understand what you suggest Daniel. What should fileFromU2 be?
>>
>> I may be wrong by using the Client method in the first place. ?? The purpose
>> of my script is to use an API which is set up as a SOAP service.
>>
>> Why would I need to download the WSDL file and then pass it to the transport
>> hack when I can¹t even get the WSDL and the purpose of client = Client (WSDL)
>> is to connect to the WSDL itself?
>>
>> Cheers
>>
>> Janet
>>
>>
>> On 7/10/10 09:33, "Daniel Rodriguez" <danjrod(a)gmail.com> wrote:
>>
>>> Hi,
>>>
>>> I think the problem is in the connect itself.
>>>
>>> The standard transport included in suds assumes that only the SOAP calls may
>>> need authentication or other things. Downloading the WSDL is attempted with
>>> a plain HTTP GET (Not even POST is allowed)
>>>
>>> I guess that the transport covers at least 95% of standard situations, but
>>> it didn't for example cover mine, where I wanted to embed the WSDSL as a
>>> string in my code. Of course only with my own transport I could give suds a
>>> "file" object with the content of the string.
>>>
>>> It is my feeling that a better transport could be written (we have seen some
>>> examples shared in the mailing list) although some use cases may require
>>> re-thinking how a Client is initialized.
>>>
>>> In the case pertaining to Janet, I guess she may download the WSDL file as
>>> you suggest, pass it to the transport hack below. She may then use this
>>> transport during client initialization. Obviously this is only good for 1
>>> WSDL file. (The transport below can also load WSDL content directly from a
>>> string)
>>>
>>> class TransportHack(Transport):
>>> def __init__(self, wsdlFile=None, **kwargs):
>>> Transport.__init__(self, **kwargs)
>>> self.wsdlcontent = wsdlFile
>>>
>>> def open(self, request):
>>> if self.wsdlFile is not None:
>>> return self.wsdlFile
>>>
>>> log.debug('opening: (%s)', request.url)
>>> fp = None
>>> location = request.url.lstrip()
>>> if location.startswith('<?'):
>>> log.debug('returning url (%s) as StringIO file')
>>> fp = StringIO(location)
>>> else:
>>> parsed = urlparse(request.url)
>>> if parsed.scheme == 'file':
>>> log.debug('opening file (%s) with open', parsed.path)
>>> try:
>>> fp = open(parsed.path)
>>> except Exception, e:
>>> raise TransportError(str(e), 503, StringIO(''))
>>> else:
>>> log.debug('opening scheme (%s) over the network',
>>> parsed.scheme)
>>> try:
>>> url = request.url
>>> log.debug('opening (%s)', url)
>>> u2request = u2.Request(url)
>>> self.proxy = self.options.proxy
>>> return self.u2open(u2request)
>>> except u2.HTTPError, e:
>>> raise TransportError(str(e), e.code, e.fp)
>>> return fp
>>>
>>> Then do something like
>>>
>>>> myClient = suds.client.Client(wsdl, transport=HackTransport(fileFromU2),
>>>> etc)
>>>
>>>
>>> Best regards
>>>
>>> Daniel
>>>
>>> On Wed, Oct 6, 2010 at 21:22, Joshua J. Kugler <joshua(a)eeinternet.com>
>>> wrote:
>>>> On Wednesday 06 October 2010, Janet Valbuena elucidated thus:
>>>>> > Hi
>>>>> >
>>>>> > I'm new to suds (have just downloaded it after getting frustrated
>>>>> > with SOAPpy).
>>>>> >
>>>>> > I'm trying to connect to a WSDL which requires basic HTTP
>>>>> > authentication. I have been able to connect to it correctly using PHP
>>>>> > but I need to use Python.
>>>>> >
>>>>> >
>>>>> > This is my code:
>>>>> >
>>>>> > #!/usr/bin/python
>>>>> >
>>>>> > Username = "user"
>>>>> > Password = "pass123"
>>>>> > from suds.transport.http import HttpAuthenticated
>>>>> > t = HttpAuthenticated(username=Username, password=Password)
>>>>> >
>>>>> > # WSDL is only available in internal network
>>>>> > WSDL = "http://localhost:18080/external/services/DomService?wsdl"
>>>>> > from suds.client import Client
>>>>> > client = Client(WSDL, transport=t)
>>>>> >
>>>>> >
>>>>> >
>>>>> >
>>>>> > And this is the error it returns:
>>>>> >
>>>>> > Traceback (most recent call last):
>>>>> > File "./wsdltest.py", line 25, in <module>
>>>>> > client = Client(wsdl, transport=t)
>>>>> > File "build/bdist.linux-i686/egg/suds/client.py", line 112, in
>>>>> > __init__ File "build/bdist.linux-i686/egg/suds/reader.py", line 152,
>>>>> > in open File "build/bdist.linux-i686/egg/suds/wsdl.py", line 136, in
>>>>> > __init__ File "build/bdist.linux-i686/egg/suds/reader.py", line 79,
>>>>> > in open File "build/bdist.linux-i686/egg/suds/reader.py", line 101,
>>>>> > in download File "build/bdist.linux-i686/egg/suds/sax/parser.py",
>>>>> > line 136, in parse File "/usr/lib/python2.5/xml/sax/expatreader.py",
>>>>> > line 107, in parse xmlreader.IncrementalParser.parse(self, source)
>>>>> > File "/usr/lib/python2.5/xml/sax/xmlreader.py", line 125, in parse
>>>>> > self.close()
>>>>> > File "/usr/lib/python2.5/xml/sax/expatreader.py", line 217, in
>>>>> > close self.feed("", isFinal = 1)
>>>>> > File "/usr/lib/python2.5/xml/sax/expatreader.py", line 211, in feed
>>>>> > self._err_handler.fatalError(exc)
>>>>> > File "/usr/lib/python2.5/xml/sax/handler.py", line 38, in
>>>>> > fatalError raise exception
>>>>> > xml.sax._exceptions.SAXParseException: <unknown>:1:0: no element
>>>>> > found
>>>>
>>>> I would try to download the file with a quick urllib2 script and see
>>>> what you get. The error is not in the connect (that would raise its
>>>> own exception) but in trying to parse what *is* being downloaded.
>>>>
>>>> Something like:
>>>>
>>>> import urllib2
>>>> auth_handler = urllib2.HTTPBasicAuthHandler()
>>>> auth_handler.add_password(realm='name_of_your_realm',
>>>> uri='your_url_without_the_file_name',
>>>> user=User,
>>>> passwd=Password)
>>>> opener = urllib2.build_opener(auth_handler)
>>>> urllib2.install_opener(opener)
>>>>
>>>> print urllib2.open(WSDL).read()
>>>>
>>>> j
>>>>
>>>> --
>>>> Joshua Kugler
>>>> Part-Time System Admin/Programmer
>>>> http://www.eeinternet.com - Fairbanks, AK
>>>> PGP Key: http://pgp.mit.edu/ ID 0x73B13B6A
>>>> _______________________________________________
>>>> suds mailing list
>>>> suds(a)lists.fedoraproject.org
>>>> https://admin.fedoraproject.org/mailman/listinfo/suds
>>>
>>>
>>
>
>
13 years, 6 months
Re: [Fedora-suds-list] Error connecting to WSDL that requires authentication
by Janet Valbuena
Joshua, Daniel
Thanks very much for your quick response.
I tried Joshua¹s suggestion but it didn¹t work.
I don¹t understand what you suggest Daniel. What should fileFromU2 be?
I may be wrong by using the Client method in the first place. ?? The purpose
of my script is to use an API which is set up as a SOAP service.
Why would I need to download the WSDL file and then pass it to the transport
hack when I can¹t even get the WSDL and the purpose of client = Client
(WSDL) is to connect to the WSDL itself?
Cheers
Janet
On 7/10/10 09:33, "Daniel Rodriguez" <danjrod(a)gmail.com> wrote:
> Hi,
>
> I think the problem is in the connect itself.
>
> The standard transport included in suds assumes that only the SOAP calls may
> need authentication or other things. Downloading the WSDL is attempted with a
> plain HTTP GET (Not even POST is allowed)
>
> I guess that the transport covers at least 95% of standard situations, but it
> didn't for example cover mine, where I wanted to embed the WSDSL as a string
> in my code. Of course only with my own transport I could give suds a "file"
> object with the content of the string.
>
> It is my feeling that a better transport could be written (we have seen some
> examples shared in the mailing list) although some use cases may require
> re-thinking how a Client is initialized.
>
> In the case pertaining to Janet, I guess she may download the WSDL file as you
> suggest, pass it to the transport hack below. She may then use this transport
> during client initialization. Obviously this is only good for 1 WSDL file.
> (The transport below can also load WSDL content directly from a string)
>
> class TransportHack(Transport):
> def __init__(self, wsdlFile=None, **kwargs):
> Transport.__init__(self, **kwargs)
> self.wsdlcontent = wsdlFile
>
> def open(self, request):
> if self.wsdlFile is not None:
> return self.wsdlFile
>
> log.debug('opening: (%s)', request.url)
> fp = None
> location = request.url.lstrip()
> if location.startswith('<?'):
> log.debug('returning url (%s) as StringIO file')
> fp = StringIO(location)
> else:
> parsed = urlparse(request.url)
> if parsed.scheme == 'file':
> log.debug('opening file (%s) with open', parsed.path)
> try:
> fp = open(parsed.path)
> except Exception, e:
> raise TransportError(str(e), 503, StringIO(''))
> else:
> log.debug('opening scheme (%s) over the network',
> parsed.scheme)
> try:
> url = request.url
> log.debug('opening (%s)', url)
> u2request = u2.Request(url)
> self.proxy = self.options.proxy
> return self.u2open(u2request)
> except u2.HTTPError, e:
> raise TransportError(str(e), e.code, e.fp)
> return fp
>
> Then do something like
>
>> myClient = suds.client.Client(wsdl, transport=HackTransport(fileFromU2), etc)
>
>
> Best regards
>
> Daniel
>
> On Wed, Oct 6, 2010 at 21:22, Joshua J. Kugler <joshua(a)eeinternet.com> wrote:
>> On Wednesday 06 October 2010, Janet Valbuena elucidated thus:
>>> > Hi
>>> >
>>> > I'm new to suds (have just downloaded it after getting frustrated
>>> > with SOAPpy).
>>> >
>>> > I'm trying to connect to a WSDL which requires basic HTTP
>>> > authentication. I have been able to connect to it correctly using PHP
>>> > but I need to use Python.
>>> >
>>> >
>>> > This is my code:
>>> >
>>> > #!/usr/bin/python
>>> >
>>> > Username = "user"
>>> > Password = "pass123"
>>> > from suds.transport.http import HttpAuthenticated
>>> > t = HttpAuthenticated(username=Username, password=Password)
>>> >
>>> > # WSDL is only available in internal network
>>> > WSDL = "http://localhost:18080/external/services/DomService?wsdl"
>>> > from suds.client import Client
>>> > client = Client(WSDL, transport=t)
>>> >
>>> >
>>> >
>>> >
>>> > And this is the error it returns:
>>> >
>>> > Traceback (most recent call last):
>>> > File "./wsdltest.py", line 25, in <module>
>>> > client = Client(wsdl, transport=t)
>>> > File "build/bdist.linux-i686/egg/suds/client.py", line 112, in
>>> > __init__ File "build/bdist.linux-i686/egg/suds/reader.py", line 152,
>>> > in open File "build/bdist.linux-i686/egg/suds/wsdl.py", line 136, in
>>> > __init__ File "build/bdist.linux-i686/egg/suds/reader.py", line 79,
>>> > in open File "build/bdist.linux-i686/egg/suds/reader.py", line 101,
>>> > in download File "build/bdist.linux-i686/egg/suds/sax/parser.py",
>>> > line 136, in parse File "/usr/lib/python2.5/xml/sax/expatreader.py",
>>> > line 107, in parse xmlreader.IncrementalParser.parse(self, source)
>>> > File "/usr/lib/python2.5/xml/sax/xmlreader.py", line 125, in parse
>>> > self.close()
>>> > File "/usr/lib/python2.5/xml/sax/expatreader.py", line 217, in
>>> > close self.feed("", isFinal = 1)
>>> > File "/usr/lib/python2.5/xml/sax/expatreader.py", line 211, in feed
>>> > self._err_handler.fatalError(exc)
>>> > File "/usr/lib/python2.5/xml/sax/handler.py", line 38, in
>>> > fatalError raise exception
>>> > xml.sax._exceptions.SAXParseException: <unknown>:1:0: no element
>>> > found
>>
>> I would try to download the file with a quick urllib2 script and see
>> what you get. The error is not in the connect (that would raise its
>> own exception) but in trying to parse what *is* being downloaded.
>>
>> Something like:
>>
>> import urllib2
>> auth_handler = urllib2.HTTPBasicAuthHandler()
>> auth_handler.add_password(realm='name_of_your_realm',
>> uri='your_url_without_the_file_name',
>> user=User,
>> passwd=Password)
>> opener = urllib2.build_opener(auth_handler)
>> urllib2.install_opener(opener)
>>
>> print urllib2.open(WSDL).read()
>>
>> j
>>
>> --
>> Joshua Kugler
>> Part-Time System Admin/Programmer
>> http://www.eeinternet.com - Fairbanks, AK
>> PGP Key: http://pgp.mit.edu/ ID 0x73B13B6A
>> _______________________________________________
>> suds mailing list
>> suds(a)lists.fedoraproject.org
>> https://admin.fedoraproject.org/mailman/listinfo/suds
>
>
13 years, 6 months
Error connecting to WSDL that requires authentication
by Janet Valbuena
Hi
I'm new to suds (have just downloaded it after getting frustrated with
SOAPpy).
I'm trying to connect to a WSDL which requires basic HTTP authentication. I
have been able to connect to it correctly using PHP but I need to use
Python.
This is my code:
#!/usr/bin/python
Username = "user"
Password = "pass123"
from suds.transport.http import HttpAuthenticated
t = HttpAuthenticated(username=Username, password=Password)
# WSDL is only available in internal network
WSDL = "http://localhost:18080/external/services/DomService?wsdl"
from suds.client import Client
client = Client(WSDL, transport=t)
And this is the error it returns:
Traceback (most recent call last):
File "./wsdltest.py", line 25, in <module>
client = Client(wsdl, transport=t)
File "build/bdist.linux-i686/egg/suds/client.py", line 112, in __init__
File "build/bdist.linux-i686/egg/suds/reader.py", line 152, in open
File "build/bdist.linux-i686/egg/suds/wsdl.py", line 136, in __init__
File "build/bdist.linux-i686/egg/suds/reader.py", line 79, in open
File "build/bdist.linux-i686/egg/suds/reader.py", line 101, in download
File "build/bdist.linux-i686/egg/suds/sax/parser.py", line 136, in parse
File "/usr/lib/python2.5/xml/sax/expatreader.py", line 107, in parse
xmlreader.IncrementalParser.parse(self, source)
File "/usr/lib/python2.5/xml/sax/xmlreader.py", line 125, in parse
self.close()
File "/usr/lib/python2.5/xml/sax/expatreader.py", line 217, in close
self.feed("", isFinal = 1)
File "/usr/lib/python2.5/xml/sax/expatreader.py", line 211, in feed
self._err_handler.fatalError(exc)
File "/usr/lib/python2.5/xml/sax/handler.py", line 38, in fatalError
raise exception
xml.sax._exceptions.SAXParseException: <unknown>:1:0: no element found
Any help would be really appreciated.
Thanks in advance!
Janet
13 years, 6 months
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13 years, 7 months
