Re: [Fedora-suds-list] Error connecting to WSDL that requires authentication

[Janet Valbuena]

Joshua, Daniel

Thanks very much for your quick response.

I tried Joshua¹s suggestion but it didn¹t work.

I don¹t understand what you suggest Daniel. What should fileFromU2 be?

I may be wrong by using the Client method in the first place. ?? The purpose
of my script is to use an API which is set up as a SOAP service.

Why would I need to download the WSDL file and then pass it to the transport
hack when I can¹t even get the WSDL and the purpose of client = Client
(WSDL) is to connect to the WSDL itself?

Cheers

Janet

On 7/10/10 09:33, "Daniel Rodriguez" <danjrod(a)gmail.com&gt; wrote:

>  Hi,
>  
>  I think the problem is in the connect itself.
>  
>  The standard transport included in suds assumes that only the SOAP calls may
>  need authentication or other things. Downloading the WSDL is attempted with a
>  plain HTTP GET (Not even POST is allowed)
>  
>  I guess that the transport covers at least 95% of standard situations, but it
>  didn't for example cover mine, where I wanted to embed the WSDSL as a string
>  in my code. Of course only with my own transport I could give suds a "file"
>  object with the content of the string.
>  
>  It is my feeling that a better transport could be written (we have seen some
>  examples shared in the mailing list) although some use cases may require
>  re-thinking how a Client is initialized.
>  
>  In the case pertaining to Janet, I guess she may download the WSDL file as you
>  suggest, pass it to the transport hack below. She may then use this transport
>  during client initialization. Obviously this is only good for 1 WSDL file.
>  (The transport below can also load WSDL content directly from a string)
>  
>      class TransportHack(Transport):
>          def __init__(self, wsdlFile=None, **kwargs):
>              Transport.__init__(self, **kwargs)
>              self.wsdlcontent = wsdlFile
>  
>          def open(self, request):
>              if self.wsdlFile is not None:
>                  return self.wsdlFile
>  
>              log.debug('opening: (%s)', request.url)
>              fp = None
>              location = request.url.lstrip()
>              if location.startswith('<?'):
>                  log.debug('returning url (%s) as StringIO file')
>                  fp = StringIO(location)
>              else:
>                  parsed = urlparse(request.url)
>                  if parsed.scheme == 'file':
>                      log.debug('opening file (%s) with open', parsed.path)
>                      try:
>                          fp = open(parsed.path)
>                      except Exception, e:
>                          raise TransportError(str(e), 503, StringIO(''))
>                  else:
>                      log.debug('opening scheme (%s) over the network',
>  parsed.scheme)
>                      try:
>                          url = request.url
>                          log.debug('opening (%s)', url)
>                          u2request = u2.Request(url)
>                          self.proxy = self.options.proxy
>                          return self.u2open(u2request)
>                      except u2.HTTPError, e:
>                          raise TransportError(str(e), e.code, e.fp)
>              return fp
>  
>  Then do something like
>  
> > myClient = suds.client.Client(wsdl, transport=HackTransport(fileFromU2), etc)
>  
>  
>  Best regards
>  
>  Daniel
>  
>  On Wed, Oct 6, 2010 at 21:22, Joshua J. Kugler <joshua(a)eeinternet.com&gt; wrote:
> > On Wednesday 06 October 2010, Janet Valbuena elucidated thus:
> >> > Hi
> >> >
> >> > I'm new to suds (have just downloaded it after getting frustrated
> >> > with SOAPpy).
> >> >
> >> > I'm trying to connect to a WSDL which requires basic HTTP
> >> > authentication. I have been able to connect to it correctly using PHP
> >> > but I need to use Python.
> >> >
> >> >
> >> > This is my code:
> >> >
> >> > #!/usr/bin/python
> >> >
> >> > Username = "user"
> >> > Password = "pass123"
> >> > from suds.transport.http import HttpAuthenticated
> >> > t = HttpAuthenticated(username=Username, password=Password)
> >> >
> >> > # WSDL is only available in internal network
> >> > WSDL = "http://localhost:18080/external/services/DomService?wsdl"
> >> > from suds.client import Client
> >> > client = Client(WSDL, transport=t)
> >> >
> >> >
> >> >
> >> >
> >> > And this is the error it returns:
> >> >
> >> > Traceback (most recent call last):
> >> >   File "./wsdltest.py", line 25, in <module>
> >> >     client = Client(wsdl, transport=t)
> >> >   File "build/bdist.linux-i686/egg/suds/client.py", line 112, in
> >> > __init__ File "build/bdist.linux-i686/egg/suds/reader.py", line
> 152,
> >> > in open File "build/bdist.linux-i686/egg/suds/wsdl.py", line 136,
> in
> >> > __init__ File "build/bdist.linux-i686/egg/suds/reader.py", line
> 79,
> >> > in open File "build/bdist.linux-i686/egg/suds/reader.py", line
> 101,
> >> > in download File "build/bdist.linux-i686/egg/suds/sax/parser.py",
> >> > line 136, in parse File
> "/usr/lib/python2.5/xml/sax/expatreader.py",
> >> > line 107, in parse xmlreader.IncrementalParser.parse(self, source)
> >> >   File "/usr/lib/python2.5/xml/sax/xmlreader.py", line 125, in
> parse
> >> >     self.close()
> >> >   File "/usr/lib/python2.5/xml/sax/expatreader.py", line 217, in
> >> > close self.feed("", isFinal = 1)
> >> >   File "/usr/lib/python2.5/xml/sax/expatreader.py", line 211, in
> feed
> >> >     self._err_handler.fatalError(exc)
> >> >   File "/usr/lib/python2.5/xml/sax/handler.py", line 38, in
> >> > fatalError raise exception
> >> > xml.sax._exceptions.SAXParseException: <unknown>:1:0: no element
> >> > found
> > 
> > I would try to download the file with a quick urllib2 script and see
> > what you get.  The error is not in the connect (that would raise its
> > own exception) but in trying to parse what *is* being downloaded.
> > 
> > Something like:
> > 
> > import urllib2
> > auth_handler = urllib2.HTTPBasicAuthHandler()
> > auth_handler.add_password(realm='name_of_your_realm',
> >                           uri='your_url_without_the_file_name',
> >                           user=User,
> >                           passwd=Password)
> > opener = urllib2.build_opener(auth_handler)
> > urllib2.install_opener(opener)
> > 
> > print urllib2.open(WSDL).read()
> > 
> > j
> > 
> > --
> > Joshua Kugler
> > Part-Time System Admin/Programmer
> > http://www.eeinternet.com - Fairbanks, AK
> > PGP Key: http://pgp.mit.edu/  ID 0x73B13B6A
> > _______________________________________________
> > suds mailing list
> > suds(a)lists.fedoraproject.org
> > https://admin.fedoraproject.org/mailman/listinfo/suds
>  
>

Error connecting to WSDL that requires authentication

[Daniel Rodriguez]

Hi Janet,

The code provided by Joshua lets you download the WSDL to a "file" object.
That's why the last statement of his example is:

print urllib2.open(WSDL).read()


whis is basically first opening a file (open), then reading the content to a
string (read) and printing it to standard output. If you simply do:

fileFromU2 = urllib2.open(WSDL)


you get direct acess to the file object and can pass it to the hacked
transport I provided before.

Best regards

Daniel

On Thu, Oct 7, 2010 at 13:03, Janet Valbuena <janet.valbuena(a)tpp.com.au&gt;wrote:

>   Joshua, Daniel
>
>  Thanks very much for your quick response.
>
>  I tried Joshua’s suggestion but it didn’t work.
>
>  I don’t understand what you suggest Daniel. What should fileFromU2 be?
>
>  I may be wrong by using the Client method in the first place. ?? The
>  purpose of my script is to use an API which is set up as a SOAP service.
>
>  Why would I need to download the WSDL file and then pass it to the
>  transport hack when I can’t even get the WSDL and the purpose of *client =
>  Client (WSDL)* is to connect to the WSDL itself?
>
>  Cheers
>
>  Janet
>
>
>  On 7/10/10 09:33, "Daniel Rodriguez" <danjrod(a)gmail.com&gt; wrote:
>
>  Hi,
>
>  I think the problem is in the connect itself.
>
>  The standard transport included in suds assumes that only the SOAP calls
>  may need authentication or other things. Downloading the WSDL is attempted
>  with a plain HTTP GET (Not even POST is allowed)
>
>  I guess that the transport covers at least 95% of standard situations, but
>  it didn't for example cover mine, where I wanted to embed the WSDSL as a
>  string in my code. Of course only with my own transport I could give suds a
>  "file" object with the content of the string.
>
>  It is my feeling that a better transport could be written (we have seen
>  some examples shared in the mailing list) although some use cases may
>  require re-thinking how a Client is initialized.
>
>  In the case pertaining to Janet, I guess she may download the WSDL file as
>  you suggest, pass it to the transport hack below. She may then use this
>  transport during client initialization. Obviously this is only good for 1
>  WSDL file. (The transport below can also load WSDL content directly from a
>  string)
>
>      class TransportHack(Transport):
>          def __init__(self, wsdlFile=None, **kwargs):
>              Transport.__init__(self, **kwargs)
>              self.wsdlcontent = wsdlFile
>
>          def open(self, request):
>              if self.wsdlFile is not None:
>                  return self.wsdlFile
>
>              log.debug('opening: (%s)', request.url)
>              fp = None
>              location = request.url.lstrip()
>              if location.startswith('<?'):
>                  log.debug('returning url (%s) as StringIO file')
>                  fp = StringIO(location)
>              else:
>                  parsed = urlparse(request.url)
>                  if parsed.scheme == 'file':
>                      log.debug('opening file (%s) with open', parsed.path)
>                      try:
>                          fp = open(parsed.path)
>                      except Exception, e:
>                          raise TransportError(str(e), 503, StringIO(''))
>                  else:
>                      log.debug('opening scheme (%s) over the network',
>  parsed.scheme)
>                      try:
>                          url = request.url
>                          log.debug('opening (%s)', url)
>                          u2request = u2.Request(url)
>                          self.proxy = self.options.proxy
>                          return self.u2open(u2request)
>                      except u2.HTTPError, e:
>                          raise TransportError(str(e), e.code, e.fp)
>              return fp
>
>  Then do something like
>
>  myClient = suds.client.Client(wsdl, transport=HackTransport(fileFromU2),
>  etc)
>
>
>
>  Best regards
>
>  Daniel
>
>  On Wed, Oct 6, 2010 at 21:22, Joshua J. Kugler <joshua(a)eeinternet.com&gt;
>  wrote:
>
>  On Wednesday 06 October 2010, Janet Valbuena elucidated thus:
>  > Hi
>  >
>  > I'm new to suds (have just downloaded it after getting frustrated
>  > with SOAPpy).
>  >
>  > I'm trying to connect to a WSDL which requires basic HTTP
>  > authentication. I have been able to connect to it correctly using PHP
>  > but I need to use Python.
>  >
>  >
>  > This is my code:
>  >
>  > #!/usr/bin/python
>  >
>  > Username = "user"
>  > Password = "pass123"
>  > from suds.transport.http import HttpAuthenticated
>  > t = HttpAuthenticated(username=Username, password=Password)
>  >
>  > # WSDL is only available in internal network
>  > WSDL = "http://localhost:18080/external/services/DomService?wsdl"
>  > from suds.client import Client
>  > client = Client(WSDL, transport=t)
>  >
>  >
>  >
>  >
>  > And this is the error it returns:
>  >
>  > Traceback (most recent call last):
>  >   File "./wsdltest.py", line 25, in <module>
>  >     client = Client(wsdl, transport=t)
>  >   File "build/bdist.linux-i686/egg/suds/client.py", line 112, in
>  > __init__ File "build/bdist.linux-i686/egg/suds/reader.py", line 152,
>  > in open File "build/bdist.linux-i686/egg/suds/wsdl.py", line 136, in
>  > __init__ File "build/bdist.linux-i686/egg/suds/reader.py", line 79,
>  > in open File "build/bdist.linux-i686/egg/suds/reader.py", line 101,
>  > in download File "build/bdist.linux-i686/egg/suds/sax/parser.py",
>  > line 136, in parse File "/usr/lib/python2.5/xml/sax/expatreader.py",
>  > line 107, in parse xmlreader.IncrementalParser.parse(self, source)
>  >   File "/usr/lib/python2.5/xml/sax/xmlreader.py", line 125, in parse
>  >     self.close()
>  >   File "/usr/lib/python2.5/xml/sax/expatreader.py", line 217, in
>  > close self.feed("", isFinal = 1)
>  >   File "/usr/lib/python2.5/xml/sax/expatreader.py", line 211, in feed
>  >     self._err_handler.fatalError(exc)
>  >   File "/usr/lib/python2.5/xml/sax/handler.py", line 38, in
>  > fatalError raise exception
>  > xml.sax._exceptions.SAXParseException: <unknown>:1:0: no element
>  > found
>
>  I would try to download the file with a quick urllib2 script and see
>  what you get.  The error is not in the connect (that would raise its
>  own exception) but in trying to parse what *is* being downloaded.
>
>  Something like:
>
>  import urllib2
>  auth_handler = urllib2.HTTPBasicAuthHandler()
>  auth_handler.add_password(realm='name_of_your_realm',
>                            uri='your_url_without_the_file_name',
>                            user=User,
>                            passwd=Password)
>  opener = urllib2.build_opener(auth_handler)
>  urllib2.install_opener(opener)
>
>  print urllib2.open(WSDL).read()
>
>  j
>
>  --
>  Joshua Kugler
>  Part-Time System Admin/Programmer
>  http://www.eeinternet.com - Fairbanks, AK
>  PGP Key: http://pgp.mit.edu/  ID 0x73B13B6A
>  _______________________________________________
>  suds mailing list
>  suds(a)lists.fedoraproject.org
>  https://admin.fedoraproject.org/mailman/listinfo/suds
>
>
>
>
>