I tried to build a kernel. In this section of code I had an issue:
# now run oldconfig over all the config files for i in *.config do mv $i .config Arch=`head -1 .config | cut -b 3-` make ARCH=$Arch listnewconfig | grep -E '^CONFIG_' >.newoptions || true if [ -s .newoptions ]; then cat .newoptions exit 1 fi rm -f .newoptions make ARCH=$Arch oldnoconfig echo "# $Arch" > configs/$i cat .config >> configs/$i done
This is from the log: + mv kernel-2.6.42.7-i686-PAE.config .config ++ head -1 .config ++ cut -b 3- + Arch=i386 + grep -E '^CONFIG_' + make ARCH=i386 listnewconfig + '[' -s .newoptions ']' + cat .newoptions CONFIG_XEN + exit 1
What happens is that running "make ARCH=i386 listnewconfig", reports CONFIG_XEN as new.
If I manually add "CONFIG_XEN=n" to .config, and run "make oldconfig", then CONFIG_XEN is removed. This - I think - means that CONFIG_XEN is an old option. But then I am baffled why is it output by "make ARCH=i386 listnewconfig" or even " "make listnewconfig". I can make no sense of it. Does anybody have an explanation?
Anyway, the way I solved this build issue was by putting "CONFIG_XEN=n" in config-local, and this way I can build, still I am curious.