Re: BASH and wildcard expansion

[inode0]

On Mon, Aug 19, 2013 at 1:56 PM, Mark Haney <mark.haney(a)gmail.com&gt; wrote:
>  I've hit a problem I can't quite figure out which a bash
> script I'm writing.
>  I'm trying to copy backup files in the format 2013-August-18--1123.zip to an
>  NFS share.  I want to have the script copy the file with just the date.  In
>  bash I've setup vars that get the current date:
>
>  # Date variables
>  log_year=`date "+%Y"`
>  log_month=`date "+%B"`
>  log_day=`date "+%d"`
>
>  # Filename format YYYY_MM_DD--HHMM.zip
>
> filename=$log_year"-"$log_month"-"$log_day"--"/*".zip"
>
>  The problem is I don't really care about the stuff after the '--'. I.e. from
>  the CLI I'd just 'ls 2013-August-18--*.zip' to get all the files with that
>  date in the file name.  How can I do that in a bash script? 
If you just want the list you can do basically the same thing you do
from the CLI.

ls $log_year"-"$log_month"-"$log_day"--*.zip

If you want to act on each file individually then maybe a loop.

Assuming your script is running in the same directory as the files
something like this maybe?

for f in $log_year"-"$log_month"-"$log_day"--*.zip; do
  // do whatever you want with $f here
done

John